25 Jan
2007
25 Jan
'07
10:51 p.m.
The correct math is
2 * 4294967296 + (4294967296 - 1834563852) = 11,050,338,036
- Brian
________________________________
From: Carl Howell [mailto:chowell@uwf.edu] Sent: Thursday, January 25, 2007 1:20 PM To: toasters@mathworks.com Subject: SNMP Question
What would be the correct way to calculate the total size of an aggregate with the following SNMP information:
dfHighTotalKBytes = 2
dfLowTotalKBytes = -1834563852
I thought it would be 2*4294967295 + 1834563852 = 10,424,498,442
But this comes out 625,839,594 short of the df -rk output:
Aggregate total = 11,050,338,036
The MIB is at version 1.17.3.
Thanks,
--Carl