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From: Carl Howell [mailto:chowell@uwf.edu]
Sent: Thursday, January 25, 2007 1:20 PM
To: toasters@mathworks.com
Subject: SNMP Question

What would be the correct way to calculate the total size of an aggregate with the following SNMP information:

 

dfHighTotalKBytes = 2

dfLowTotalKBytes = -1834563852

 

I thought it would be 2*4294967295 + 1834563852 = 10,424,498,442

 

But this comes out 625,839,594 short of the df –rk output:

 

Aggregate total = 11,050,338,036

 

The MIB is at version 1.17.3.

 

Thanks,

 

--Carl