25 Jan
2007
25 Jan
'07
9:20 p.m.
What would be the correct way to calculate the total size of an aggregate with the following SNMP information:
dfHighTotalKBytes = 2
dfLowTotalKBytes = -1834563852
I thought it would be 2*4294967295 + 1834563852 = 10,424,498,442
But this comes out 625,839,594 short of the df -rk output:
Aggregate total = 11,050,338,036
The MIB is at version 1.17.3.
Thanks,
--Carl