What would be the correct way to calculate the total size of an aggregate with the following SNMP information:

dfHighTotalKBytes = 2

dfLowTotalKBytes = -1834563852

I thought it would be 2*4294967295 + 1834563852 = 10,424,498,442

But this comes out 625,839,594 short of the df –rk output:

Aggregate total = 11,050,338,036

The MIB is at version 1.17.3.

Thanks,

--Carl