No, not true (yet).
I was misinformed, though I do believe it's a planned feature. At the moment the filer's not bright enough to store the block once in cache.
________________________________
From: Page, Jeremy [mailto:jeremy.page@gilbarco.com] Sent: Thu 11/13/2008 17:05 To: Todd C. Merrill; Darren Sykes Cc: Glenn Walker; toasters@mathworks.com Subject: RE: de-dup of memory? (was Re: Snapvault slow on one specific volume?)
I don't know :)
In theory it should work. When you request data you're not requesting it from the disk, your asking for a specific block. If that block is in cache it should not matter if it's deduped (and pretending to be several blocks) or not.
-----Original Message----- From: Todd C. Merrill [mailto:tmerrill@mathworks.com] Sent: Thursday, November 13, 2008 12:04 PM To: Darren Sykes Cc: Glenn Walker; Page, Jeremy; toasters@mathworks.com Subject: de-dup of memory? (was Re: Snapvault slow on one specific volume?)
On Wed, 15 Oct 2008, Darren Sykes wrote:
I¹d say it was probably the bug; in theory dedup should increase performance in that situation as the block would be stored in the cache and therefore we wouldn¹t need to go to disk to get that data.
Is this true?
Is memory "de-dup'ed" as well? That is, when you access a file through the cache, if it ends up at a de-dup'ed block, is it really the same block in *memory*, too? Or, is the path through memory/cache unique and only the final disk store de-dup'ed?
Until next time...
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