Over simplified
120*200 = 24,000 maximum sustained ops (minus parity disks)
Or
80*140 = 11,200 maximum sustained ops (minus parity disks)
-----Original Message----- From: toasters-bounces@teaparty.net [mailto:toasters-bounces@teaparty.net] On Behalf Of Ray Van Dolson Sent: Friday, September 13, 2013 3:29 PM To: toasters@teaparty.net Subject: Expected performance difference between two configurations
Hi all;
Am trying to understand what sort of performance difference I might see between two different configurations:
1) IBM N6240 E21 (FAS3240C) w/ 120x600GB 15K 3.5" SAS and 512GB of flash cache 2) IBM N6250 E26 w/ 80x900GB 10K 2.5" SAS and 512GB of flash cache.
Sorry, on the latter I don't know the equivalent FAS. Probably FAS3250C?
We have fewer spindles, but newer, beefier controllers.
Our workload is primarily VMware via NFS. Lotsa random reads and writes (more on the read side) with I'd say the bulk of the IO requests in the 64KB+ range.
Will I regret going with fewer spindles?
Ray _______________________________________________ Toasters mailing list Toasters@teaparty.net http://www.teaparty.net/mailman/listinfo/toasters